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函数原型
tf.nn.dynamic_rnn( cell, inputs, sequence_length=None, initial_state=None, dtype=None, parallel_iterations=None, swap_memory=False, time_major=False, scope=None )
实例讲解：
import tensorflow as tf
import numpy as np
n_steps = 2
n_inputs = 3
n_neurons = 5
X = tf.placeholder(tf.float32, [None, n_steps, n_inputs])
basic_cell = tf.contrib.rnn.BasicRNNCell(num_units=n_neurons)
seq_length = tf.placeholder(tf.int32, [None])
outputs, states = tf.nn.dynamic_rnn(basic_cell, X, dtype=tf.float32,
sequence_length=seq_length)
init = tf.global_variables_initializer()
X_batch = np.array([
# step 0 step 1
[[0, 1, 2], [9, 8, 7]], # instance 1
[[3, 4, 5], [0, 0, 0]], # instance 2 (padded with zero vectors)
[[6, 7, 8], [6, 5, 4]], # instance 3
[[9, 0, 1], [3, 2, 1]], # instance 4
])
seq_length_batch = np.array([2, 1, 2, 2])
with tf.Session() as sess:
init.run()
outputs_val, states_val = sess.run(
[outputs, states], feed_dict={X: X_batch, seq_length: seq_length_batch})
print("outputs_val.shape:", outputs_val.shape, "states_val.shape:", states_val.shape)
print("outputs_val:", outputs_val, "states_val:", states_val)
log info:
outputs_val.shape: (4, 2, 5) states_val.shape: (4, 5) outputs_val: [[[ 0.53073734 -0.61281306 -0.5437517 0.7320347 -0.6109526 ] [ 0.99996936 0.99990636 -0.9867181 0.99726075 -0.99999976]] [[ 0.9931584 0.5877845 -0.9100412 0.988892 -0.9982337 ] [ 0. 0. 0. 0. 0. ]] [[ 0.99992317 0.96815354 -0.985101 0.9995968 -0.9999936 ] [ 0.99948144 0.9998127 -0.57493806 0.91015154 -0.99998355]] [[ 0.99999255 0.9998929 0.26732785 0.36024097 -0.99991137] [ 0.98875254 0.9922327 0.6505734 0.4732064 -0.9957567 ]]] states_val: [[ 0.99996936 0.99990636 -0.9867181 0.99726075 -0.99999976] [ 0.9931584 0.5877845 -0.9100412 0.988892 -0.9982337 ] [ 0.99948144 0.9998127 -0.57493806 0.91015154 -0.99998355] [ 0.98875254 0.9922327 0.6505734 0.4732064 -0.9957567 ]]
首先输入X是一个 [batch_size，step，input_size] = [4，2，3] 的tensor，注意我们这里调用的是BasicRNNCell，只有一层循环网络，outputs是最后一层每个step的输出，它的结构是[batch_size，step，n_neurons] = [4，2，5]，states是每一层的最后那个step的输出，由于本例中，我们的循环网络只有一个隐藏层，所以它就代表这一层的最后那个step的输出，因此它和step的大小是没有关系的，我们的X有4个样本组成，输出神经元大小n_neurons是5，因此states的结构就是[batch_size，n_neurons] = [4，5]，最后我们观察数据，states的每条数据正好就是outputs的最后一个step的输出。
下面我们继续讲解多个隐藏层的情况，这里是三个隐藏层，注意我们这里仍然是调用BasicRNNCell
import tensorflow as tf
import numpy as np
n_steps = 2
n_inputs = 3
n_neurons = 5
n_layers = 3
X = tf.placeholder(tf.float32, [None, n_steps, n_inputs])
seq_length = tf.placeholder(tf.int32, [None])
layers = [tf.contrib.rnn.BasicRNNCell(num_units=n_neurons,
activation=tf.nn.relu)
for layer in range(n_layers)]
multi_layer_cell = tf.contrib.rnn.MultiRNNCell(layers)
outputs, states = tf.nn.dynamic_rnn(multi_layer_cell, X, dtype=tf.float32, sequence_length=seq_length)
init = tf.global_variables_initializer()
X_batch = np.array([
# step 0 step 1
[[0, 1, 2], [9, 8, 7]], # instance 1
[[3, 4, 5], [0, 0, 0]], # instance 2 (padded with zero vectors)
[[6, 7, 8], [6, 5, 4]], # instance 3
[[9, 0, 1], [3, 2, 1]], # instance 4
])
seq_length_batch = np.array([2, 1, 2, 2])
with tf.Session() as sess:
init.run()
outputs_val, states_val = sess.run(
[outputs, states], feed_dict={X: X_batch, seq_length: seq_length_batch})
print("outputs_val.shape:", outputs, "states_val.shape:", states)
print("outputs_val:", outputs_val, "states_val:", states_val)
log info:
outputs_val.shape:
Tensor("rnn/transpose_1:0", shape=(?, 2, 5), dtype=float32)
states_val.shape:
(<tf.Tensor 'rnn/while/Exit_3:0' shape=(?, 5) dtype=float32>,
<tf.Tensor 'rnn/while/Exit_4:0' shape=(?, 5) dtype=float32>,
<tf.Tensor 'rnn/while/Exit_5:0' shape=(?, 5) dtype=float32>)
outputs_val:
[[[0. 0. 0. 0. 0. ]
[0. 0.18740742 0. 0.2997518 0. ]]
[[0. 0.07222144 0. 0.11551574 0. ]
[0. 0. 0. 0. 0. ]]
[[0. 0.13463384 0. 0.21534224 0. ]
[0.03702604 0.18443246 0. 0.34539366 0. ]]
[[0. 0.54511094 0. 0.8718864 0. ]
[0.5382122 0. 0.04396425 0.4040263 0. ]]]
states_val:
(array([[0. , 0.83723307, 0. , 0. , 2.8518028 ],
[0. , 0.1996038 , 0. , 0. , 1.5456247 ],
[0. , 1.1372368 , 0. , 0. , 0.832613 ],
[0. , 0.7904129 , 2.4675028 , 0. , 0.36980057]],
dtype=float32),
array([[0.6524607 , 0. , 0. , 0. , 0. ],
[0.25143963, 0. , 0. , 0. , 0. ],
[0.5010576 , 0. , 0. , 0. , 0. ],
[0. , 0.3166597 , 0.4545995 , 0. , 0. ]],
dtype=float32),
array([[0. , 0.18740742, 0. , 0.2997518 , 0. ],
[0. , 0.07222144, 0. , 0.11551574, 0. ],
[0.03702604, 0.18443246, 0. , 0.34539366, 0. ],
[0.5382122 , 0. , 0.04396425, 0.4040263 , 0. ]],
dtype=float32))
我们说过，outputs是最后一层的输出，即 [batch_size，step，n_neurons] = [4，2，5]
states是每一层的最后一个step的输出，即三个结构为 [batch_size，n_neurons] = [4，5] 的tensor
继续观察数据，states中的最后一个array，正好是outputs的最后那个step的输出
下面我们继续讲当由BasicLSTMCell构造单元工厂的时候，只讲多层的情况，我们只需要将上面的BasicRNNCell替换成BasicLSTMCell就行了，打印信息如下：
outputs_val.shape:
Tensor("rnn/transpose_1:0", shape=(?, 2, 5), dtype=float32)
states_val.shape:
(LSTMStateTuple(c=<tf.Tensor 'rnn/while/Exit_3:0' shape=(?, 5) dtype=float32>,
h=<tf.Tensor 'rnn/while/Exit_4:0' shape=(?, 5) dtype=float32>),
LSTMStateTuple(c=<tf.Tensor 'rnn/while/Exit_5:0' shape=(?, 5) dtype=float32>,
h=<tf.Tensor 'rnn/while/Exit_6:0' shape=(?, 5) dtype=float32>),
LSTMStateTuple(c=<tf.Tensor 'rnn/while/Exit_7:0' shape=(?, 5) dtype=float32>,
h=<tf.Tensor 'rnn/while/Exit_8:0' shape=(?, 5) dtype=float32>))
outputs_val:
[[[1.2949290e-04 0.0000000e+00 2.7623639e-04 0.0000000e+00 0.0000000e+00]
[9.4675866e-05 0.0000000e+00 2.0214770e-04 0.0000000e+00 0.0000000e+00]]
[[4.3100454e-06 4.2123037e-07 1.4312843e-06 0.0000000e+00 0.0000000e+00]
[0.0000000e+00 0.0000000e+00 0.0000000e+00 0.0000000e+00 0.0000000e+00]]
[[0.0000000e+00 0.0000000e+00 0.0000000e+00 0.0000000e+00 0.0000000e+00]
[0.0000000e+00 0.0000000e+00 0.0000000e+00 0.0000000e+00 0.0000000e+00]]
[[0.0000000e+00 0.0000000e+00 0.0000000e+00 0.0000000e+00 0.0000000e+00]
[0.0000000e+00 0.0000000e+00 0.0000000e+00 0.0000000e+00 0.0000000e+00]]]
states_val:
(LSTMStateTuple(
c=array([[0. , 0. , 0.04676079, 0.04284539, 0. ],
[0. , 0. , 0.0115245 , 0. , 0. ],
[0. , 0. , 0. , 0. , 0. ],
[0. , 0. , 0. , 0. , 0. ]],
dtype=float32),
h=array([[0. , 0. , 0.00035096, 0.04284406, 0. ],
[0. , 0. , 0.00142574, 0. , 0. ],
[0. , 0. , 0. , 0. , 0. ],
[0. , 0. , 0. , 0. , 0. ]],
dtype=float32)),
LSTMStateTuple(
c=array([[0.0000000e+00, 1