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本文实例讲述了asp.net(C#)实现功能强大的时间日期处理类。分享给大家供大家参考,具体如下:
using System; using System.Data; using System.Configuration; using System.Web; using System.Web.Security; using System.Web.UI; using System.Web.UI.WebControls; using System.Web.UI.WebControls.WebParts; using System.Web.UI.HtmlControls; namespace MSCL { /// <summary> /// 时间日期处理类 /// </summary> public class DateTimeHelper { #region 返回本年有多少天 /// <summary>返回本年有多少天</summary> /// <param name="iYear">年份</param> /// <returns>本年的天数</returns> public static int GetDaysOfYear(int iYear) { int cnt = 0; if (IsRuYear(iYear)) { //闰年多 1 天 即:2 月为 29 天 cnt = 366; } else { //--非闰年少1天 即:2 月为 28 天 cnt = 365; } return cnt; } #endregion #region 返回本年有多少天 /// <summary>本年有多少天</summary> /// <param name="dt">日期</param> /// <returns>本天在当年的天数</returns> public static int GetDaysOfYear(DateTime idt) { int n; //取得传入参数的年份部分,用来判断是否是闰年 n = idt.Year; if (IsRuYear(n)) { //闰年多 1 天 即:2 月为 29 天 return 366; } else { //--非闰年少1天 即:2 月为 28 天 return 365; } } #endregion #region 返回本月有多少天 /// <summary>本月有多少天</summary> /// <param name="iYear">年</param> /// <param name="Month">月</param> /// <returns>天数</returns> public static int GetDaysOfMonth(int iYear, int Month) { int days = 0; switch (Month) { case 1: days = 31; break; case 2: if (IsRuYear(iYear)) { //闰年多 1 天 即:2 月为 29 天 days = 29; } else { //--非闰年少1天 即:2 月为 28 天 days = 28; } break; case 3: days = 31; break; case 4: days = 30; break; case 5: days = 31; break; case 6: days = 30; break; case 7: days = 31; break; case 8: days = 31; break; case 9: days = 30; break; case 10: days = 31; break; case 11: days = 30; break; case 12: days = 31; break; } return days; } #endregion #region 返回本月有多少天 /// <summary>本月有多少天</summary> /// <param name="dt">日期</param> /// <returns>天数</returns> public static int GetDaysOfMonth(DateTime dt) { //--------------------------------// //--从dt中取得当前的年,月信息 --// //--------------------------------// int year, month, days = 0; year = dt.Year; month = dt.Month; //--利用年月信息,得到当前月的天数信息。 switch (month) { case 1: days = 31; break; case 2: if (IsRuYear(year)) { //闰年多 1 天 即:2 月为 29 天 days = 29; } else { //--非闰年少1天 即:2 月为 28 天 days = 28; } break; case 3: days = 31; break; case 4: days = 30; break; case 5: days = 31; break; case 6: days = 30; break; case 7: days = 31; break; case 8: days = 31; break; case 9: days = 30; break; case 10: days = 31; break; case 11: days = 30; break; case 12: days = 31; break; } return days; } #endregion #region 返回当前日期的星期名称 /// <summary>返回当前日期的星期名称</summary> /// <param name="dt">日期</param> /// <returns>星期名称</returns> public static string GetWeekNameOfDay(DateTime idt) { string dt, week = ""; dt = idt.DayOfWeek.ToString(); switch (dt) { case "Mondy": week = "星期一"; break; case "Tuesday": week = "星期二"; break; case "Wednesday": week = "星期三"; break; case "Thursday": week = "星期四"; break; case "Friday": week = "星期五"; break; case "Saturday": week = "星期六"; break; case "Sunday": week = "星期日"; break; } return week; } #endregion #region 返回当前日期的星期编号 /// <summary>返回当前日期的星期编号</summary> /// <param name="dt">日期</param> /// <returns>星期数字编号</returns> public static string GetWeekNumberOfDay(DateTime idt) { string dt, week = ""; dt = idt.DayOfWeek.ToString(); switch (dt) { case "Mondy": week = "1"; break; case "Tuesday": week = "2"; break; case "Wednesday": week = "3"; break; case "Thursday": week = "4"; break; case "Friday": week = "5"; break; case "Saturday": week = "6"; break; case "Sunday": week = "7"; break; } return week; } #endregion #region 判断当前日期所属的年份是否是闰年,私有函数 /// <summary>判断当前日期所属的年份是否是闰年,私有函数</summary> /// <param name="dt">日期</param> /// <returns>是闰年:True ,不是闰年:False</returns> private static bool IsRuYear(DateTime idt) { //形式参数为日期类型 //例如:2003-12-12 int n; n = idt.Year; if ((n % 400 == 0) || (n % 4 == 0 && n % 100 != 0)) { return true; } else { return false; } } #endregion #region 判断当前年份是否是闰年,私有函数 /// <summary>判断当前年份是否是闰年,私有函数</summary> /// <param name="dt">年份</param> /// <returns>是闰年:True ,不是闰年:False</returns> private static bool IsRuYear(int iYear) { //形式参数为年份 //例如:2003 int n; n = iYear; if ((n % 400 == 0) || (n % 4 == 0 && n % 100 != 0)) { return true; } else { return false; } } #endregion #region 将输入的字符串转化为日期。如果字符串的格式非法,则返回当前日期 /// <summary> /// 将输入的字符串转化为日期。如果字符串的格式非法,则返回当前日期。 /// </summary> /// <param name="strInput">输入字符串</param> /// <returns>日期对象</returns> public static DateTime ConvertStringToDate(string strInput) { DateTime oDateTime; try { oDateTime = DateTime.Parse(strInput); } catch (Exception) { oDateTime = DateTime.Today; } return oDateTime; } #endregion #region 将日期对象转化为格式字符串 /// <summary> /// 将日期对象转化为格式字