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本文实例讲述了asp.net(C#)实现功能强大的时间日期处理类。分享给大家供大家参考,具体如下:
using System;
using System.Data;
using System.Configuration;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
namespace MSCL
{
/// <summary>
/// 时间日期处理类
/// </summary>
public class DateTimeHelper
{
#region 返回本年有多少天
/// <summary>返回本年有多少天</summary>
/// <param name="iYear">年份</param>
/// <returns>本年的天数</returns>
public static int GetDaysOfYear(int iYear)
{
int cnt = 0;
if (IsRuYear(iYear))
{
//闰年多 1 天 即:2 月为 29 天
cnt = 366;
}
else
{
//--非闰年少1天 即:2 月为 28 天
cnt = 365;
}
return cnt;
}
#endregion
#region 返回本年有多少天
/// <summary>本年有多少天</summary>
/// <param name="dt">日期</param>
/// <returns>本天在当年的天数</returns>
public static int GetDaysOfYear(DateTime idt)
{
int n;
//取得传入参数的年份部分,用来判断是否是闰年
n = idt.Year;
if (IsRuYear(n))
{
//闰年多 1 天 即:2 月为 29 天
return 366;
}
else
{
//--非闰年少1天 即:2 月为 28 天
return 365;
}
}
#endregion
#region 返回本月有多少天
/// <summary>本月有多少天</summary>
/// <param name="iYear">年</param>
/// <param name="Month">月</param>
/// <returns>天数</returns>
public static int GetDaysOfMonth(int iYear, int Month)
{
int days = 0;
switch (Month)
{
case 1:
days = 31;
break;
case 2:
if (IsRuYear(iYear))
{
//闰年多 1 天 即:2 月为 29 天
days = 29;
}
else
{
//--非闰年少1天 即:2 月为 28 天
days = 28;
}
break;
case 3:
days = 31;
break;
case 4:
days = 30;
break;
case 5:
days = 31;
break;
case 6:
days = 30;
break;
case 7:
days = 31;
break;
case 8:
days = 31;
break;
case 9:
days = 30;
break;
case 10:
days = 31;
break;
case 11:
days = 30;
break;
case 12:
days = 31;
break;
}
return days;
}
#endregion
#region 返回本月有多少天
/// <summary>本月有多少天</summary>
/// <param name="dt">日期</param>
/// <returns>天数</returns>
public static int GetDaysOfMonth(DateTime dt)
{
//--------------------------------//
//--从dt中取得当前的年,月信息 --//
//--------------------------------//
int year, month, days = 0;
year = dt.Year;
month = dt.Month;
//--利用年月信息,得到当前月的天数信息。
switch (month)
{
case 1:
days = 31;
break;
case 2:
if (IsRuYear(year))
{
//闰年多 1 天 即:2 月为 29 天
days = 29;
}
else
{
//--非闰年少1天 即:2 月为 28 天
days = 28;
}
break;
case 3:
days = 31;
break;
case 4:
days = 30;
break;
case 5:
days = 31;
break;
case 6:
days = 30;
break;
case 7:
days = 31;
break;
case 8:
days = 31;
break;
case 9:
days = 30;
break;
case 10:
days = 31;
break;
case 11:
days = 30;
break;
case 12:
days = 31;
break;
}
return days;
}
#endregion
#region 返回当前日期的星期名称
/// <summary>返回当前日期的星期名称</summary>
/// <param name="dt">日期</param>
/// <returns>星期名称</returns>
public static string GetWeekNameOfDay(DateTime idt)
{
string dt, week = "";
dt = idt.DayOfWeek.ToString();
switch (dt)
{
case "Mondy":
week = "星期一";
break;
case "Tuesday":
week = "星期二";
break;
case "Wednesday":
week = "星期三";
break;
case "Thursday":
week = "星期四";
break;
case "Friday":
week = "星期五";
break;
case "Saturday":
week = "星期六";
break;
case "Sunday":
week = "星期日";
break;
}
return week;
}
#endregion
#region 返回当前日期的星期编号
/// <summary>返回当前日期的星期编号</summary>
/// <param name="dt">日期</param>
/// <returns>星期数字编号</returns>
public static string GetWeekNumberOfDay(DateTime idt)
{
string dt, week = "";
dt = idt.DayOfWeek.ToString();
switch (dt)
{
case "Mondy":
week = "1";
break;
case "Tuesday":
week = "2";
break;
case "Wednesday":
week = "3";
break;
case "Thursday":
week = "4";
break;
case "Friday":
week = "5";
break;
case "Saturday":
week = "6";
break;
case "Sunday":
week = "7";
break;
}
return week;
}
#endregion
#region 判断当前日期所属的年份是否是闰年,私有函数
/// <summary>判断当前日期所属的年份是否是闰年,私有函数</summary>
/// <param name="dt">日期</param>
/// <returns>是闰年:True ,不是闰年:False</returns>
private static bool IsRuYear(DateTime idt)
{
//形式参数为日期类型
//例如:2003-12-12
int n;
n = idt.Year;
if ((n % 400 == 0) || (n % 4 == 0 && n % 100 != 0))
{
return true;
}
else
{
return false;
}
}
#endregion
#region 判断当前年份是否是闰年,私有函数
/// <summary>判断当前年份是否是闰年,私有函数</summary>
/// <param name="dt">年份</param>
/// <returns>是闰年:True ,不是闰年:False</returns>
private static bool IsRuYear(int iYear)
{
//形式参数为年份
//例如:2003
int n;
n = iYear;
if ((n % 400 == 0) || (n % 4 == 0 && n % 100 != 0))
{
return true;
}
else
{
return false;
}
}
#endregion
#region 将输入的字符串转化为日期。如果字符串的格式非法,则返回当前日期
/// <summary>
/// 将输入的字符串转化为日期。如果字符串的格式非法,则返回当前日期。
/// </summary>
/// <param name="strInput">输入字符串</param>
/// <returns>日期对象</returns>
public static DateTime ConvertStringToDate(string strInput)
{
DateTime oDateTime;
try
{
oDateTime = DateTime.Parse(strInput);
}
catch (Exception)
{
oDateTime = DateTime.Today;
}
return oDateTime;
}
#endregion
#region 将日期对象转化为格式字符串
/// <summary>
/// 将日期对象转化为格式字

