在C#中创建和读取XML文件的实现方法

1.创建简单的XML文件
为了便于测试，我们首先创建控制台应用程序，项目命名为CreateXml，Program.cs代码如下：

namespace CreateXml
{
    class Program
    {
        static void Main(string[] args)
        {
            Program app = new Program();
            app.CreateXmlFile();         
        }
        public void CreateXmlFile()
        {
            XmlDocument xmlDoc = new XmlDocument();
            //创建类型声明节点
            XmlNode node=xmlDoc.CreateXmlDeclaration("1.0","utf-8","");
            xmlDoc.AppendChild(node);
            //创建根节点
            XmlNode root = xmlDoc.CreateElement("User");
            xmlDoc.AppendChild(root);
            CreateNode(xmlDoc, root, "name", "xuwei");
            CreateNode(xmlDoc, root, "sex", "male");
            CreateNode(xmlDoc, root, "age", "25");
            try
            {
                xmlDoc.Save("c://data2.xml");
            }
            catch (Exception e)
            {
                //显示错误信息
                Console.WriteLine(e.Message);
            }
            //Console.ReadLine();

        }

        /// <summary> 
        /// 创建节点 
        /// </summary> 
        /// <param name="xmldoc"></param>  xml文档
        /// <param name="parentnode"></param>父节点 
        /// <param name="name"></param>  节点名
        /// <param name="value"></param>  节点值
        ///
        public void CreateNode(XmlDocument xmlDoc,XmlNode parentNode,string name,string value)
        {
            XmlNode node = xmlDoc.CreateNode(XmlNodeType.Element, name, null);
            node.InnerText = value;
            parentNode.AppendChild(node);
        }
    } 
}
</div>
这样会在C盘根目录下创建data2.xml文件，文件内容为

            XmlNode node2 = xmlDoc.CreateNode(XmlNodeType.Element, "User", null);
            CreateNode(xmlDoc, node2, "name", "xiaolai");
            CreateNode(xmlDoc, node2, "sex", "female");
            CreateNode(xmlDoc, node2, "age", "23");
            root.AppendChild(node2);

            try
            {
                xmlDoc.Save("c://data5.xml");
            }
            catch (Exception e)
            {
                //显示错误信息
                Console.WriteLine(e.Message);