jquery实现ajax提交form表单的方法总结

方法一：

        {
            var AjaxURL= "../OrderManagement/AjaxModifyOrderService.aspx";      
            alert($('#formAddHandlingFee').serialize());
                $.ajax({
                    type: "POST",
                    dataType: "html",
                    url: AjaxURL + '?Action=' + 'SubmitHandlingFee' + '&OrderNumber=' + $.trim($("#<%=this.txtOrderNumber.ClientID %>").val()),
                    data: $('#formAddHandlingFee').serialize(),
                    success: function (result) {
                        var strresult=result;
                        alert(strresult);
                        //加载最大可退金额
                        $("#spanMaxAmount").html(strresult);
                    },
                    error: function(data) {
                        alert("error:"+data.responseText);
                     }

                });

        }

方法二：

                });
        }

    );

页面html代码：