Android安全专项之Xposed劫持用户名密码实践
Xposed是个强大的工具,可以hook所有的java方法,下面用Xposed来截获App的用户名密码,默认你已经安装好Xposed环境了
AS中创建带有Login界面的项目
然后一路Next
,创建成功后,运行,App
界面如下:<喎?http://www.Bkjia.com/kf/ware/vc/" target="_blank" class="keylink">vcD4NCjxwPjxpbWcgYWx0PQ=="这里写图片描述" src="http://www.bkjia.com/uploads/allimg/160311/041H955X-1.png" title="\" />
为了使用Xposed
劫持应用的用户名和密码,我们需要知道该应用的包名和要hook
的方法,我们只要找到点击SIGN IN OR REGISTER
按钮的点击事件处理方法,只要hook这个方法,我们就能获取到输入框中的信息。
xposed.doctorq.com.qq4xposed
hook的方法:xposed.doctorq.com.qq4xposed.LoginActivity.attemptLogin
在hook
的beforeHookedMethod
方法中获取下面两个属性的值:
Xposed Module
Xposed Module
称为Xposed插件,利用Xposed进行实际劫持的项目。
我们创建一个不带界面的Android项目,创建一个类,实现IXposedHookLoadPackage
:
public class LoginHook implements IXposedHookLoadPackage{
@Override
public void handleLoadPackage(XC_LoadPackage.LoadPackageParam loadPackageParam) throws Throwable {
if(!loadPackageParam.packageName.equals("xposed.doctorq.com.qq4xposed")) return;
findAndHookMethod("xposed.doctorq.com.qq4xposed.LoginActivity", loadPackageParam.classLoader, "attemptLogin", new XC_MethodHook() {
@Override
protected void beforeHookedMethod(MethodHookParam param) throws Throwable {
XposedBridge.log("已经HOOK");
Class o = param.thisObject.getClass();
XposedBridge.log(o.getName());
Field.setAccessible(o.getDeclaredFields(), true);
Field fieldEmail = findField(o, "mEmailView");
Field fieldPassword = findField(o,"mPasswordView");
AutoCompleteTextView autoTextView = (AutoCompleteTextView)fieldEmail.get(param.thisObject);
EditText editText = (EditText)fieldPassword.get(param.thisObject);
String email = autoTextView.getText().toString();
String password = editText.getText().toString();
Toast.makeText((Activity)param.thisObject,"邮箱: " + email + ",密码 : " + password,Toast.LENGTH_LONG).show();
}
@Override
protected void afterHookedMethod(MethodHookParam param) throws Throwable {
}
});
}
}
将xposed_init
文件修改如下:
安装该应用,在Xposed Installer
中勾选,重启生效,操作之前的App
,正常输入邮箱和密码:
总结
使用Xposed进行hook的时候,难点不是如何使用Xposed,而是如何找到要被hook的方法,比如你如何hook QQ登录方法,这就需要反编译QQ的Apk找到登录入口,要是学会这一点,随便一个App你都能Hook。
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